
(1)由图甲得:
R1=
| P1 | ||
|
| 6W |
| (1A)2 |
由图甲、乙得:
| P2 |
| P′2 |
| ||
|
| ||
|
| 1 |
| 9 |
| I1 |
| I2 |
| 1 |
| 3 |
解得:I2=3A;
(2)
| U1 |
| U2 |
| I1(R2+R3) |
| I2R2 |
| R2+R3 |
| 3R2 |
| 7 |
| 3 |
解得:R3=6R2,
根据电源两端电压不变,由图甲、乙得:
I1(R1+R2+R3)=I2(R1+R2),
解得:R2=3Ω,
根据图乙得:
U=I2(R1+R2)=3A×(6Ω+3Ω)=27V;
(3)当闭合开关S后,将滑动变阻器的滑片P置于滑动变阻器中点时,通过R2的电流
I=
| U | ||
R1+R2+
|