如图,电源电压为6V R1=4Ω R2=6Ω 资源ID:355121866 1、I=U/R总州雹=6/(4+6)=0.6A2、W1=I²册者帆R1t=0.6²×4×10=14. 1、I=U/R总州雹=6/(4+6)=0.6A2、W1=I²册者帆R1t=0.6²×4×10=14.4J W2=I²R2t=0.6²×6×10=21.6J3、P=U²/R并嫌猛总=6²/2.4=15W (1/R并总=1/R1+1/R2=2.4Ω)(1)I=U/宽搏(R1+R2)=6/(4+6)=0.6A(2)W1=I^2R1t=0.6^2*4*10=14.4JW2=^2R2t=0.6^2*6*10=21.6J(3)P1=U^2/埋咐R1=36/4=9WP2=U^2/慎液祥R2=36/6=6WP=P1+P2=15W ← 上一篇:简答题服装配色原则有哪些 下一篇:时装摄影如何拍摄得时髦又潮流? →